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Proof step 4 from proof bits2int-rec-04 (previous step)

¬(true ∧ bits.first ∧ false ∈ bits), bits.first ⊦ bits2int(bits + true ') = bits2int(bits) * 2 + 1, bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
bits.first ⊦ bits = [], bits2int(bits + true ') = ~1, false ∈ bits

Rule argument

Additional information

Used simplifier rules: bits2int-ones: ⊦ ¬ false ∈ bits ∧ bits ≠ [] → bits2int(bits) = ~1;