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Proof step 5 from proof bits2int-rec-04 (previous step)

bits.first ⊦ bits = [], bits2int(bits + true ') = ~1, false ∈ bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ ¬ false ∈ bits ∧ bits ≠ [] → bits2int(bits) = ~1

Rule argument

name: bits2int-ones rotate: F subst: [bits] → [bits + true ']

Additional information

Used simplifier rules: ⊦ boolvar ∈ bits + bits0 ↔ ¬ ¬(boolvar ∈ bits ∨ boolvar ∈ bits0);% ⊦ boolvar ∈ boolvar0 ' ↔ boolvar ↔ boolvar0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = []; Used terms: bits + true '