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Proof step 1 from proof bits2int-zero-02 (conclusion)

⊦ bits ≠ [] → (bits2int(bits) = 0 ↔ ¬ true ∈ bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bits2int(bits) = 0, true ∈ bits ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: bits2int-zero-01: ⊦ ¬ true ∈ bits ∧ bits ≠ [] → bits2int(bits) = 0;