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Proof step 2 from proof bits2int-zero-02 (previous step)

bits2int(bits) = 0, true ∈ bits ⊦ bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bits ≠ [] ∧ bits.first → bits2int(bits) = bits2uint(bits) - 2 ^ n→i(# bits)
Proof step 4:
¬(bits ≠ [] ∧ bits.first), bits2int(bits) = 0, true ∈ bits ⊦ bits = []
Proof step 6:
bits ≠ [] ∧ bits.first, bits2uint(bits) - 2 ^ n→i(# bits) = 0, true ∈ bits ⊦ bits = []

Rule argument

name: bits2ubits rotate: F subst: [bits] → [bits]

Additional information

Used terms: bits