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Proof step 1 from proof bits2ubits (conclusion)

⊦ bits ≠ [] ∧ bits.first → bits2int(bits) = bits2uint(bits) - 2 ^ n→i(# bits)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bits.first ⊦ bits = [], bits2uint(bits) = bits2int(bits) + 2 ^ n→i(# bits)

Rule argument

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j;