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Proof step 2 from proof bits2ubits (previous step)

bits.first ⊦ bits = [], bits2uint(bits) = bits2int(bits) + 2 ^ n→i(# bits)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ bits ≠ [] ∧ bits.first → bits2uint(bits) = bits2int(bits) + 2 ^ n→i(# bits)

Rule argument

name: ubits2bits rotate: T subst: [bits] → [bits]

Additional information

Used terms: bits