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Proof step 2 from proof bits2uint-nle-01 (previous step)

# bits ≤ n, 2 ^ n→i(n) ≤ bits2uint(bits) ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 3:
bits2uint(bits) < 2 ^ n→i(# bits), # bits ≤ n, 2 ^ n→i(n) ≤ bits2uint(bits) ⊦

Rule argument

fma: bits2uint(bits) < 2 ^ n→i(# bits)

Additional information

Used simplifier rules: bits2uint-nle: ⊦ ¬ 2 ^ n→i(# bits) ≤ bits2uint(bits);% ⊦ ¬ i < j ↔ j ≤ i; Used formulas: bits2uint(bits) < 2 ^ n→i(# bits)