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Proof step 3 from proof bits2uint-nle-01 (previous step)

bits2uint(bits) < 2 ^ n→i(# bits), # bits ≤ n, 2 ^ n→i(n) ≤ bits2uint(bits) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
bits2uint(bits) < 2 ^ n→i(# bits), # bits ≤ n, 2 ^ n→i(n) ≤ bits2uint(bits), 2 ^ n→i(n) < 2 ^ n→i(# bits) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)