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Proof step 7 from proof int2bits-2pot-neg-mone (previous step)

0 < j ∧ 0 < i, 0 < j, 0 < i, 0 ≤ i ⊦ uint2bits(j - 1) + mklist(true, i→n(i)) = int2bits(j - 1) + mklist(true, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 < j, 0 < i, 0 ≤ i ⊦ uint2bits(j - 1) = int2bits(j - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + bits0 = bits1 + bits0 ↔ bits = bits1;