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Proof step 8 from proof int2bits-2pot-neg-mone (previous step)

0 < j, 0 < i, 0 ≤ i ⊦ uint2bits(j - 1) = int2bits(j - 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
0 ≤ i ⊦ int2bits((* i)) = uint2bits(i)

Rule argument

name: int2bits-pos-num rotate: F subst: [i] → [j - 1]

Additional information

Used simplifier rules: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: j - 1