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Proof step 1 from proof int2bits-bits2unit-01 (conclusion)

⊦ i < 0 → int2bits(bits2uint(int2bits(i))) = sgn(false ' + int2bits(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 0 ⊦ int2bits(bits2uint(int2bits(i))) = sgn(false ' + int2bits(i))

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)