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Proof step 2 from proof int2bits-bits2unit-01 (previous step)

i < 0 ⊦ int2bits(bits2uint(int2bits(i))) = sgn(false ' + int2bits(i))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < 0 → int2bits(i) = sgn(bitsinvert(uint2bits(abs(i))) +1)
Proof step 4:
i < 0, i < 0 ⊦ int2bits(bits2uint(sgn(bitsinvert(uint2bits(abs(i))) +1))) = sgn(false ' + sgn(bitsinvert(uint2bits(abs(i))) +1))

Rule argument

name: int2bits-neg rotate: F subst: [i] → [i]

Additional information

Used terms: i