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Proof step 4 from proof int2bits-expos (previous step)

uint2bits(i) = false ' + true ' + bits, false ∈ uint2bits(i), 0 < i ⊦ ∃ bits. int2bits(i) = false ' + true ' + bits

User applied rule exists right

And obtained the following new goals

Proof step 5:
uint2bits(i) = false ' + true ' + bits, false ∈ uint2bits(i), 0 < i ⊦ int2bits(i) = false ' + true ' + bits

Rule argument

pos: right 1 terms: bits abort: F discard: T computed: T

Additional information

Used terms: bits