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Proof step 5 from proof int2bits-expos (
previous step
)
uint2bits(i) = false ' + true ' + bits, false ∈ uint2bits(i), 0 < i ⊦ int2bits(i) = false ' + true ' + bits
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
uint2bits(i) = false ' + true ' + bits, false ∈ uint2bits(i), 0 < i ⊦ int2bits(i) = uint2bits(i)
Rule argument
Additional information