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Proof step 7 from proof int2bits-lelen-07 (previous step)

2 ^ n→i(# int2bits(~ j)) + j ≤ 0 ⊦ j < 0, ¬ 0 ≤ j ∧ j + 2 ^ n→i(# int2bits(~ j)) ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
2 ^ n→i(# int2bits(~ j)) + j ≤ 0, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;% ⊦ ¬ i < j ↔ j ≤ i;