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Proof step 8 from proof int2bits-lelen-07 (previous step)

2 ^ n→i(# int2bits(~ j)) + j ≤ 0, 0 ≤ j ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i ≠ j → (i ≤ j ↔ i < j)
Proof step 10:
¬ 2 ^ n→i(# int2bits(~ j)) + j ≠ 0, 2 ^ n→i(# int2bits(~ j)) + j ≤ 0, 0 ≤ j ⊦
Proof step 11:
2 ^ n→i(# int2bits(~ j)) + j ≠ 0, 2 ^ n→i(# int2bits(~ j)) + j < 0, 0 ≤ j ⊦

Rule argument

seq: ⊦ i ≠ j → (i ≤ j ↔ i < j) subst: [j, i] → [0, 2 ^ n→i(# int2bits(~ j)) + j] rotate: F spec: int-abs inst: name: lels-02

Additional information

Used terms: 0, 2 ^ n→i(# int2bits(~ j)) + j