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Proof step 2 from proof int2bits-len-eq-01 (previous step)

2 ^ n→i(# int2bits(~ j)) + j = 0 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 3:
2 ^ n→i(# int2bits(~ j)) + j = 0 ⊦ 2 ^ n→i(# int2bits(~ j)) = ~ j

Rule argument

fma: 2 ^ n→i(# int2bits(~ j)) = ~ j

Additional information

Used simplifier rules: int2bits-len-eq: ⊦ j ≠ 2 ^ n→i(# int2bits(j)); Used formulas: 2 ^ n→i(# int2bits(~ j)) = ~ j