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Proof step 3 from proof int2bits-len-eq-01 (previous step)

2 ^ n→i(# int2bits(~ j)) + j = 0 ⊦ 2 ^ n→i(# int2bits(~ j)) = ~ j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i + j = 0 ↔ i = ~ j

Rule argument

seq: ⊦ i + j = 0 ↔ i = ~ j subst: [j, i] → [j, 2 ^ n→i(# int2bits(~ j))] rotate: F spec: int-abs inst: name: rew-eqzero

Additional information

Used terms: j, 2 ^ n→i(# int2bits(~ j))