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Proof step 4 from proof int2bits-len-mod2pot (previous step)

¬ 0 < j % 2 ^ i, 0 < i, 0 < j, i→n(i) + 1 < # int2bits(j % 2 ^ i) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < i, 0 < j, i→n(i) + 1 < # int2bits(j % 2 ^ i), j % 2 ^ i ≤ 0, j % 2 ^ i < i, j % 2 ^ i < j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;