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Proof step 2 from proof int2bits-len-mod2pot (previous step)

0 < i, 0 < j, i→n(i) + 1 < # int2bits(j % 2 ^ i) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < i → (m < # int2bits(i) ↔ ¬ i < 2 ^ (n→i(m) - 1))
Proof step 4:
¬ 0 < j % 2 ^ i, 0 < i, 0 < j, i→n(i) + 1 < # int2bits(j % 2 ^ i) ⊦
Proof step 7:
0 < j % 2 ^ i, 0 < i, 0 < j, ¬ j % 2 ^ i < 2 ^ (n→i(i→n(i) + 1) - 1) ⊦

Rule argument

name: int2bits-lslen-06 rotate: F subst: [i, m] → [j % 2 ^ i, i→n(i) + 1]

Additional information

Used terms: j % 2 ^ i, i→n(i) + 1