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Proof step 7 from proof int2bits-len-mod2pot (previous step)

0 < j % 2 ^ i, 0 < i, 0 < j, ¬ j % 2 ^ i < 2 ^ (n→i(i→n(i) + 1) - 1) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
0 < i, 0 < j, 2 ^ i ≤ j % 2 ^ i, 0 < j % 2 ^ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + 0 = i;% ⊦ (* i) + i0 - (* j) = (i - j) + i0;% ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ 0 < i → n→i(i→n(i)) = i;% ⊦ n→i(m + n) = n→i(m) + n→i(n);