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Proof step 2 from proof int2bits-less-2pot-01 (previous step)

2 ^ (n→i(# int2bits(j)) - 1) < abs(j) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ j < 0 → abs(j) = 0 - j
Proof step 4:
¬ j < 0, 2 ^ (n→i(# int2bits(j)) - 1) < abs(j) ⊦
Proof step 7:
j < 0, 2 ^ (n→i(# int2bits(j)) - 1) < 0 - j ⊦

Rule argument

seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [j] rotate: F spec: int-abs inst: name: Abs-neg

Additional information

Used terms: j