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Proof step 7 from proof int2bits-less-2pot-01 (previous step)

j < 0, 2 ^ (n→i(# int2bits(j)) - 1) < 0 - j ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
j < 0, 2 ^ (n→i(# int2bits(j)) - 1) + j < 0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i < ~ j ↔ i + j < 0;% ⊦ 0 - i = ~ i;