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Proof step 29 from proof int2bits-rest (previous step)

(¬ false) ∈ bitsinvert(uint2bits(~(j / 2))) +1, j % 2 = 0, (sgn(bitsinvert(uint2bits(~(j / 2))) +1) + false ').rest = [], j < 0, j < ~1 ⊦ j = ~1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
j % 2 = 0, (sgn(bitsinvert(uint2bits(~(j / 2))) +1) + false ').rest = [], j < 0, j < ~1, true ∈ bitsinvert(uint2bits(~(j / 2))) +1 ⊦ j = ~1, j = 0

Proof step 29 from proof int2bits-rest (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information