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Proof step 30 from proof int2bits-rest (previous step)

j % 2 = 0, (sgn(bitsinvert(uint2bits(~(j / 2))) +1) + false ').rest = [], j < 0, j < ~1, true ∈ bitsinvert(uint2bits(~(j / 2))) +1 ⊦ j = ~1, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 31:
⊦ bits ≠ [] → (bits + bits0).rest = bits.rest + bits0

Rule argument

seq: ⊦ bits ≠ [] → (bits + bits0).rest = bits.rest + bits0 subst: [bits0, bits] → [false ', sgn(bitsinvert(uint2bits(~(j / 2))) +1)] rotate: F spec: list inst: bitlista name: rest-01

Additional information

Used simplifier rules: ⊦ ¬ bits +1 ≠ [] ↔ false;% ⊦ sgn(bits) = [] ↔ bits = [];% ⊦ ¬ bits + bits0 ≠ [] ↔ bits = [] ∧ bits0 = [];% ⊦ boolvar ' ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: false ', sgn(bitsinvert(uint2bits(~(j / 2))) +1)