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Proof step 10 from proof int2bits-truein-01 (previous step)

int2bits(j) = boolvar ' + bits, j < 0, boolvar ∈ int2bits(j) ⊦ j = 0, true ∈ bits, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 11:
boolvar, int2bits(j) = boolvar ' + bits, j < 0, boolvar ∈ int2bits(j) ⊦ j = 0, true ∈ bits, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

Rule argument

fma: boolvar

Additional information

Used simplifier rules: int2bits-first: ⊦ j < 0 → int2bits(j) ≠ false ' + bits;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used formulas: boolvar