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Proof step 11 from proof int2bits-truein-01 (previous step)

boolvar, int2bits(j) = boolvar ' + bits, j < 0, boolvar ∈ int2bits(j) ⊦ j = 0, true ∈ bits, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
int2bits(j) = true ' + bits, j < 0 ⊦ j = 0, true ∈ bits, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

Rule argument

Additional information

Used simplifier rules: int2bits-truein: ⊦ true ∈ int2bits(j) ↔ j ≠ 0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)