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Proof step 1 from proof int2int-inj (conclusion)

⊦ bits2int(int2bits(i)) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 3:
¬ 0 ≤ i ⊦ bits2int(int2bits(i)) = i
Proof step 32:
0 ≤ i ⊦ bits2int(uint2bits(i)) = i

Rule argument

name: int2bits-pos rotate: F subst: [i] → [i]

Additional information

Used terms: i