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Proof step 32 from proof int2int-inj (previous step)

0 ≤ i ⊦ bits2int(uint2bits(i)) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 33:
⊦ ¬ bits.first ∧ bits ≠ [] → bits2int(bits) = bits2uint(bits)
Proof step 34:
¬(¬ uint2bits(i).first ∧ uint2bits(i) ≠ []), 0 ≤ i ⊦ bits2int(uint2bits(i)) = i
Proof step 36:
¬ uint2bits(i).first ∧ uint2bits(i) ≠ [], 0 ≤ i ⊦ bits2uint(uint2bits(i)) = i

Rule argument

name: bits2int-pos-02 rotate: F subst: [bits] → [uint2bits(i)]

Additional information

Used terms: uint2bits(i)