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Proof step 36 from proof int2int-inj (previous step)

¬ uint2bits(i).first ∧ uint2bits(i) ≠ [], 0 ≤ i ⊦ bits2uint(uint2bits(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
0 ≤ i ⊦ bits2uint(uint2bits(i)) = i, uint2bits(i).first

Rule argument

Additional information

Used simplifier rules: uint2bits-empty: 0 ≤ i ⊦ uint2bits(i) ≠ [];% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);