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Proof step 34 from proof int2int-inj (previous step)

¬(¬ uint2bits(i).first ∧ uint2bits(i) ≠ []), 0 ≤ i ⊦ bits2int(uint2bits(i)) = i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
0 ≤ i, uint2bits(i).first ⊦ bits2int(uint2bits(i)) = i

Rule argument

Additional information

Used simplifier rules: uint2bits-empty: 0 ≤ i ⊦ uint2bits(i) ≠ [];