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Proof step 11 from proof int2int-inj (previous step)

int2bits(i).first, i < 0 ⊦ bits2uint((false ' + bitsinvert(int2bits(i).rest))+1) + i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ i < 0 → int2bits(i) = sgn(bitsinvert(uint2bits(abs(i))) +1)
Proof step 13:
i < 0, sgn(bitsinvert(uint2bits(abs(i))) +1).first, i < 0 ⊦ bits2uint((false ' + bitsinvert(sgn(bitsinvert(uint2bits(abs(i))) +1).rest))+1) + i = 0

Rule argument

name: int2bits-neg rotate: F subst: [i] → [i]

Additional information

Used terms: i