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Proof step 13 from proof int2int-inj (previous step)

i < 0, sgn(bitsinvert(uint2bits(abs(i))) +1).first, i < 0 ⊦ bits2uint((false ' + bitsinvert(sgn(bitsinvert(uint2bits(abs(i))) +1).rest))+1) + i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
i < 0, sgn(bitsinvert(uint2bits(~ i)) +1).first ⊦ bits2uint((false ' + bitsinvert(sgn(bitsinvert(uint2bits(~ i)) +1).rest))+1) + i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;