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Proof step 26 from proof ubits2ubits-def (previous step)

bits2uint(bits0) = 0, ∀ bits1. # bits1 < #(bits0 + true ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ false ' + true ' = sgn(false ' + bits0 + true ')

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
⊦ true ∈ bits → bits2uint(bits) ≠ 0
Proof step 28:
¬ true ∈ bits0, bits2uint(bits0) = 0, ∀ bits1. # bits1 < #(bits0 + true ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ false ' + true ' = sgn(false ' + bits0 + true ')

Rule argument

name: bits2uint-not-zero rotate: F subst: [bits] → [bits0]

Additional information

Used terms: bits0