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Proof step 28 from proof ubits2ubits-def (previous step)

¬ true ∈ bits0, bits2uint(bits0) = 0, ∀ bits1. # bits1 < #(bits0 + true ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ false ' + true ' = sgn(false ' + bits0 + true ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
∀ bits1. # bits1 < #(bits0 + true ') → true → uint2bits(bits2uint(bits1)) = sgn(false ' + bits1) ⊦ false ' + true ' = sgn(false ' + bits0 + true '), true ∈ bits0

Rule argument

Additional information

Used simplifier rules: bits2uint-zeros: ⊦ ¬ true ∈ bits → bits2uint(bits) = 0;