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Proof step 2 from proof uint2bits-inj (previous step)

uint2bits(i) = uint2bits(j), 0 ≤ i, 0 ≤ j ⊦ i = j

User applied rule induction

And obtained the following new goals

Proof step 3:
uint2bits(i) = uint2bits(j) ∧ 0 ≤ i ∧ 0 ≤ j, ∀ i0, j. i→n(i0) < i→n(i) → uint2bits(i0) = uint2bits(j) ∧ 0 ≤ i0 ∧ 0 ≤ j → i0 = j ⊦ i = j

Rule argument

indvar: i→n(i) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(i)