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Proof step 3 from proof uint2bits-inj (previous step)

uint2bits(i) = uint2bits(j) ∧ 0 ≤ i ∧ 0 ≤ j, ∀ i0, j. i→n(i0) < i→n(i) → uint2bits(i0) = uint2bits(j) ∧ 0 ≤ i0 ∧ 0 ≤ j → i0 = j ⊦ i = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information