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Theorem uint2bits-rec-01

⊦ 0 < i ∧ i ≠ 1 → uint2bits(i) = uint2bits(i / 2) + (i % 2 = 1)

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: int2bits-neg-03, int2bits-rec-neg, uint2bits-2pot, uint2bits-2pot-01, uint2bits-2pot-02, uint2bits-2pot-neg-mone, uint2bits-add-high, uint2bits-div2pot, uint2bits-empty, uint2bits-eq, uint2bits-expos1, uint2bits-falsein, uint2bits-falsein-01, uint2bits-first, uint2bits-inj, uint2bits-len, uint2bits-len-01, uint2bits-len-mon, uint2bits-mod2pot, uint2bits-not-one, uint2bits-pred, uint2bits-restsgn, uint2bits-second, uint2bits-succ, uint2bits-zero-01, uint2uint-inv, uint2uint-pos,
Used by units in proved state: intops, byte,
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 1
Proof steps: 2
Used lemmas: uint2bits-rec,
Used spec theorems:
- Used simplifier rules:
  - int-abs/lels-03
  - int-abs/lsone
  - int-basic1/lst-01
  - list/bitlista/Last
  - list/bitlista/app-01
  - list/bitlista/a