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Proof step 14 from proof uint2int-rest (previous step)

uint2bits(i) = false ' + true ' + bits, 0 < i ⊦ 2 ^ (1 + n→i(# bits)) = 1 + bits2uint(bitsinvert(bits)) + i

User applied rule insert lemma

And obtained the following new goals

Proof step 15:
0 < i ⊦ bits2uint(bitsinvert(uint2bits(i))) = 2 ^ n→i(# uint2bits(i)) - i + 1
Proof step 16:
bits2uint(bitsinvert(uint2bits(i))) = 2 ^ n→i(# uint2bits(i)) - i + 1, uint2bits(i) = false ' + true ' + bits, 0 < i ⊦ 2 ^ (1 + n→i(# bits)) = 1 + bits2uint(bitsinvert(bits)) + i

Rule argument

name: uint2uint-inv subst: [i] → [i]

Additional information

Used terms: i