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Proof step 16 from proof uint2int-rest (previous step)

bits2uint(bitsinvert(uint2bits(i))) = 2 ^ n→i(# uint2bits(i)) - i + 1, uint2bits(i) = false ' + true ' + bits, 0 < i ⊦ 2 ^ (1 + n→i(# bits)) = 1 + bits2uint(bitsinvert(bits)) + i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
uint2bits(i) = false ' + true ' + bits, 2 ^ n→i(# uint2bits(i)) = bits2uint(bitsinvert(uint2bits(i))) + i + 1, 0 < i ⊦ 2 ^ (1 + n→i(# bits)) = 1 + bits2uint(bitsinvert(bits)) + i

Rule argument

Additional information

Used simplifier rules: ⊦ i - j = i0 ↔ i = i0 + j;