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Proof step 10 from proof coprimes-max (previous step)

1 ≤ i, 0 < max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))), i ≤ i, 1 < max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))), i ≤ max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))), 1 < i, 0 < i, max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) ≤ i, 1 < i, 0 < i ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) = i, 1 < i, 0 < i ⊦

Rule argument

Additional information

Used simplifier rules: forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%anti: ⊦ i ≤ j → (j ≤ i ↔ i = j); from specification int-abs%ler: ⊦ i ≤ i; from specification int-abs%leone: ⊦ 1 ≤ i ↔ 0 < i; from specification int-abs