[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 11 from proof coprimes-max (previous step)

max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) = i, 1 < i, 0 < i ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 12:
⊦ ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints))
Proof step 13:
filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)) ≠ [] → max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) ∈ filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)) ∧ (∀ i0. i0 ∈ filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)) → i0 ≤ max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i)))), max(filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))) = i, 1 < i, 0 < i ⊦

Rule argument

spec: inst: name: max-def seq: ⊦ ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints)) subst: [ints] → [filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))] flags: current, []

Additional information

Used terms: filterFun(λ j. gcd(i, j) = 1, count-i2j(1, i))