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Proof step 3 from proof countFun-in-01 (previous step)

⊦ i0 ∈ countFun(i, j, intfun) ↔ (∃ j0. i ≤ j0 ∧ j0 ≤ j ∧ intfun(j0) = i0)

Lemma countFun-in