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Theorem countFun-in
⊦ i0 ∈ countFun(i, j, intfun) ↔ (∃ j0. i ≤ j0 ∧ j0 ≤ j ∧ intfun(j0) = i0)
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
countFun-in-01
,
sum-countfun-not-ls
,
Used by units in proved state:
int-mod
,
int-fac
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 6
Proof steps: 18
Used lemmas:
countFun-base-01
,
countFun-rec
,
countFun-base
,
Used spec theorems:
Used simplifier rules:
int-abs
/
elim-sub
int-abs
/
forward-le-02
int-abs
/
lels-03
int-abs
/
forward-le-01
int-basic2
/
ls
int-abs
/
lenls
list
/intlista/
a
list
/intlista/
in-17
list
/intlista/
in-append
int-abs
/
sub-add-05
intnat
/
abs-pred
int-basic2
/
add-zero
list
/intlista/
in-empty
int-abs
/
succ-01
int-abs
/
ler
int-abs
/
forward-le-05
int-basic2
/
ls-02
int-abs
/
forward-lsle
int-abs
/
lels-01
int-basic1
/
ls-01
int-basic2
/
add-c
int-basic2
/
add-a
int-abs
/
zero-gels-04
int-abs
/
lep
int-abs
/
forward-lele
int-abs
/
lels
int-abs
/
anti