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Proof step 2 from proof max-rec (previous step)

⊦ ints = [], max(i ' + ints) = max(i, max(ints))

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints))
Proof step 4:
ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints)) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Rule argument

spec: inst: name: max-def seq: ⊦ ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints)) subst: [ints] → [ints] flags: current, []

Additional information

Used terms: ints