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Proof step 4 from proof max-rec (previous step)

ints ≠ [] → max(ints) ∈ ints ∧ (∀ i. i ∈ ints → i ≤ max(ints)) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ i. i ∈ ints → i ≤ max(ints) ⊦ ints = [], max(i ' + ints) = max(i, max(ints))

Rule argument

Additional information

Used simplifier rules: max-in-01: ⊦ max(ints) ∈ ints ↔ ints ≠ [];