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Proof step 1 from proof min-one (conclusion)

⊦ min(i ') = i

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ ints ≠ [] → min(ints) ∈ ints ∧ (∀ i. i ∈ ints → min(ints) ≤ i)
Proof step 3:
i ' ≠ [] → min(i ') ∈ i ' ∧ (∀ i0. i0 ∈ i ' → min(i ') ≤ i0) ⊦ min(i ') = i

Rule argument

spec: inst: name: min-def seq: ⊦ ints ≠ [] → min(ints) ∈ ints ∧ (∀ i. i ∈ ints → min(ints) ≤ i) subst: [ints] → [i '] flags: current, []

Additional information

Used terms: i '