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Proof step 3 from proof min-one (previous step)

i ' ≠ [] → min(i ') ∈ i ' ∧ (∀ i0. i0 ∈ i ' → min(i ') ≤ i0) ⊦ min(i ') = i

User applied rule case distinction

And obtained the following new goals

Proof step 4:
min(i ') ∈ i ' ∧ (∀ i0. i0 ∈ i ' → min(i ') ≤ i0) ⊦ min(i ') = i

Rule argument

pos: left 1

Additional information

Used simplifier rules: e: ⊦ i ' ≠ []; from specification list[intlista]