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Proof step 4 from proof min-one (
previous step
)
min(i ') ∈ i ' ∧ (∀ i0. i0 ∈ i ' → min(i ') ≤ i0) ⊦ min(i ') = i
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 5
:
⊦ i ∈ i0 ' ↔ i = i0
Rule argument
spec: list inst: intlista name: in-17 seq: ⊦ i ∈ i0 ' ↔ i = i0 subst: [i0, i] → [i, min(i ')] flags: rewrite
Additional information
Used terms: i, min(i ')