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Proof step 13 from proof min-rec (previous step)

i < min(ints), min(i ' + ints) < i, min(i ' + ints) < min(ints), ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = i

User applied rule all left

And obtained the following new goals

Proof step 14:
i < min(ints), min(i ' + ints) < i, min(i ' + ints) < min(ints), ∀ i0. i0 ∈ ints → min(i ' + ints) ≤ i0, i ∈ ints → min(ints) ≤ i, ∀ i. i ∈ ints → min(ints) ≤ i ⊦ ints = [], min(i ' + ints) = i

Rule argument

pos: left 5 terms: i abort: F discard: F computed: T

Additional information

Used terms: i